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sav07_homework_1_solution [2007/03/19 12:00]
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sav07_homework_1_solution [2007/03/19 12:02] (current)
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 </​latex>​ </​latex>​
  
-holds. Namely, suppose ​ <​latex>​(x,​z) \in r \circ (s \cap t) </​latex>​.+holds. Namely, suppose ​ <​latex>​(x,​z) \in r \circ (s \cap t)</​latex>​.
 Then there is a y such Then there is a y such
-that <​latex>​(x,​y) \in r</​latex>​ and <​latex>​(y,​z) \in s \cap t</​latex>​. ​ Therefore,+that <​latex>​(x,​y) \in r</​latex>​ and <​latex>​(y,​z) \in s \cap t </​latex>​. ​ Therefore,
 <​latex>​(y,​z) \in s</​latex>​ and <​latex>​(y,​z) \in t</​latex>​. ​ From <​latex>​(x,​y) \in r</​latex>​ and <​latex>​(y,​z) \in s</​latex>​ we <​latex>​(y,​z) \in s</​latex>​ and <​latex>​(y,​z) \in t</​latex>​. ​ From <​latex>​(x,​y) \in r</​latex>​ and <​latex>​(y,​z) \in s</​latex>​ we
 have <​latex>​(x,​z) \in r \circ s</​latex>​. Similarly, have <​latex>​(x,​z) \in r \circ s</​latex>​. Similarly,