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strings_and_languages [2007/05/05 18:38]
vkuncak
strings_and_languages [2012/09/19 16:55]
vkuncak
Line 18: Line 18:
 \end{eqnarray*} \end{eqnarray*}
 Therefore, $(\Sigma^*, {\ \cdot\ }, \epsilon)$ is a [[monoid]]. Therefore, $(\Sigma^*, {\ \cdot\ }, \epsilon)$ is a [[monoid]].
 +
 +If $w$ is a word, we define $w^0 = \epsilon$ and $w^{n+1} = w \cdot w^n$.
  
 A **language** is any set of strings, that is, a set $L \subseteq \Sigma^*$. A **language** is any set of strings, that is, a set $L \subseteq \Sigma^*$.
Line 28: Line 30:
   L^0 &=& \{ \epsilon \} \\   L^0 &=& \{ \epsilon \} \\
   L^{n+1} &=& L \cdot L^n \\   L^{n+1} &=& L \cdot L^n \\
-  L^* &=& \bigcup_{n \geq 0} L^n+  L^* &=& \bigcup_{n \geq 0} L^n = \{ w_1 \ldots w_n \mid w_1,​\ldots,​w_n \in L \}
 \end{eqnarray*} \end{eqnarray*}
 +
 +==== Simple Consequences ====
 +
 +Observe that
 +\[
 +   ​\emptyset \cdot L = \{ s_1 \cdot s_2 \mid s_1 \in \emptyset \land s_2 \in L \} = \{s_1 \cdot s_2 \mid \mbox{false} \} = \emptyset
 +\]
 +Similarly, $L \cdot \emptyset = \emptyset$.
 +
 +Of course, $\{ w_1 \} \cdot \{ w_2 \} = w_1\cdot w_2$.