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sav08:using_automata_to_decide_ws1s [2010/05/21 01:45]
vkuncak
sav08:using_automata_to_decide_ws1s [2011/04/12 15:09]
vkuncak
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 ====== Using Automata to Decide WS1S ====== ====== Using Automata to Decide WS1S ======
  
-Consider a formula $F$ of [[weak_monadic_logic_of_one_successor|WS1S]] ​without quantifiers.  Let $V$ be a finite set of all variables in $F$.  We construct an automaton $A(F)$ in the finite alphabet+Consider a formula $F$ of [[weak_monadic_logic_of_one_successor|WS1S]]. ​ Let $V$ be a finite set of all variables in $F$.  We construct an automaton $A(F)$ in the finite alphabet
 \[ \[
    ​\Sigma = \Sigma_1^V    ​\Sigma = \Sigma_1^V
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         w         w
      ​______________      ​______________
-      patch(w,x,s)+      patch(w,x,b)
  
 Let $w = w_1 \ldots w_n$ where $w_i \in \Sigma$ and $b = b_1 \ldots b_m$ where $b_j \in \Sigma_1$. ​ Let $w = w_1 \ldots w_n$ where $w_i \in \Sigma$ and $b = b_1 \ldots b_m$ where $b_j \in \Sigma_1$. ​
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   * if $q$ is a final state and $zero_x \in \Sigma$ is such that $zero_x(v)=0$ for all $x \neq v$, and if $\delta(q',​zero_x)=q$,​ then set $q'$ also to be final   * if $q$ is a final state and $zero_x \in \Sigma$ is such that $zero_x(v)=0$ for all $x \neq v$, and if $\delta(q',​zero_x)=q$,​ then set $q'$ also to be final
  
-**Example:​** Compute automaton for formula $\exists X. \lnot (X \subseteq Y)$.+**Example ​1:** Compute automaton for formula $\exists X. \lnot (X \subseteq Y)$
 + 
 +**Example 2:** Compute automaton for formula $\exists Y. (X < Y)$ where $<$ is interpreted treating $X,Y$ as digits of natural numbers.
  
 ===== References ===== ===== References =====