Differences
This shows you the differences between two versions of the page.
| Both sides previous revision Previous revision Next revision | Previous revision Next revision Both sides next revision | ||
|
sav08:simple_qe_for_integer_difference_inequalities [2009/04/21 19:15] vkuncak |
sav08:simple_qe_for_integer_difference_inequalities [2009/04/21 19:17] vkuncak |
||
|---|---|---|---|
| Line 87: | Line 87: | ||
| $\forall y \exists x . x \leq y \wedge x \neq y $ | $\forall y \exists x . x \leq y \wedge x \neq y $ | ||
| - | ++|\\ | + | ++++|\\ |
| $\exists x . x \leq y \wedge (x < y \vee y < x)$\\ | $\exists x . x \leq y \wedge (x < y \vee y < x)$\\ | ||
| $\exists x . x \leq y \wedge (x + 1 \leq y \vee y + 1 \leq x)$\\ | $\exists x . x \leq y \wedge (x + 1 \leq y \vee y + 1 \leq x)$\\ | ||
| $(\exists x . x \leq y \wedge x + 1 \leq y) \vee (\exists x . x \leq y \wedge y + 1 \leq x)$\\ | $(\exists x . x \leq y \wedge x + 1 \leq y) \vee (\exists x . x \leq y \wedge y + 1 \leq x)$\\ | ||
| - | Without lower or upper bounds, formulas is $true$\\ | + | Because there are no lower or upper bounds, these formulas are $true$\\ |
| - | $\exists x . x + 0 \leq y \wedge x + 1 \leq y$ is $true$, then the entire formula is $true$ | + | ++++ |
| - | ++ | + | |
| If we apply this technique to a closed formula in this theory, what formulas do we obtain as a result? | If we apply this technique to a closed formula in this theory, what formulas do we obtain as a result? | ||