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--- sav08:relational_semantics_of_procedures [2009/05/26 17:45]
vkuncak
+++ sav08:relational_semantics_of_procedures [2009/05/26 17:48]
vkuncak
@@ Line 113: / Line 113: @@
 \]
-The results extend to any number of call sites and any number of mutually recursive procedures, we just consider a function $G : {\cal R}^d \to {\cal R}^d$ where $d$ is the number of procedures; this mapping describes how, given one approximation of procedure semantics, compute a better approximation that is correct for longer executions. We have operations $\sqsubseteq$ and $\sqcup$ analogous to $\subseteq$ and $\cup$ (indeed, the domain ${\cal R}^d$, that is $(2^{S\times S})^d$, is isomorphic to $2^{S\times S \times \{1,2,\ldots,d\}}$).
+We define lattice structure on ${\cal R}^2$ by
+\[
+   (r_1,r_2) \sqsubseteq (r'_1,r'_2) \ \mbox{iff} (r_1 \subseteq r'_1) \land (r_2 \subseteq r'_2)
+\]
+\[
+   (r_1,r_2) \sqcup (r'_1,r'_2) = (r_1 \cup r'_1, r_2 \cup r'_2)
+\]
+The results extend to any number of call sites and any number of mutually recursive procedures, we just consider a function $G : {\cal R}^d \to {\cal R}^d$ where $d$ is the number of procedures; this mapping describes how, given one approximation of procedure semantics, compute a better approximation that is correct for longer executions.
-The meaning of all procedures is therefore the tuple $p_* \in {\cal R}^n$ given by $\bigsqcup\limits_{n \ge 0} G^n(\emptyset,\ldots,\emptyset)$.
+We define $\sqsubseteq$ and $\sqcup$ analogous to $\subseteq$ and $\cup$ (indeed, the domain ${\cal R}^d$, that is $(2^{S\times S})^d$, is isomorphic to $2^{S\times S \times \{1,2,\ldots,d\}}$).
-**Remark:** $p_*$ is the least fixpoint of $G$, so by [[sav08:Tarski's Fixpoint Theorem]], it is also the least $p$ such that $G(p) \sqsubseteq p$. Thus, $G(p) \sqsubseteq p$ implies $p_* \sqsubseteq p$.
+The meaning of all procedures is then the tuple $p_* \in {\cal R}^n$ given by $\bigsqcup\limits_{n \ge 0} G^n(\emptyset,\ldots,\emptyset)$.
+**Remark:** $p_*$ is the least fixpoint of $G$, so by [[sav08:Tarski's Fixpoint Theorem]], it is also the least $p$ such that $G(p) \sqsubseteq p$. Thus, $G(p) \sqsubseteq p$ implies $p_* \sqsubseteq p$.