LARA

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sav08:qe_for_presburger_arithmetic [2009/04/23 09:55]
vkuncak
sav08:qe_for_presburger_arithmetic [2009/04/23 14:51]
vkuncak
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 We obtain a disjunction of conjunctions of literals of the form $0 < t$ and $K \mid t$ where $t$ are of the form $K_0 + \sum_{i=1}^n K_i \cdot x_i$ We obtain a disjunction of conjunctions of literals of the form $0 < t$ and $K \mid t$ where $t$ are of the form $K_0 + \sum_{i=1}^n K_i \cdot x_i$
 +
  
  
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 We first drop all constraints except divisibility,​ obtaining $F_2(x)$ We first drop all constraints except divisibility,​ obtaining $F_2(x)$
 \[ \[
-   ​\bigwedge_{i=1}^D K_i \mid (x_i + t_i)+   ​\bigwedge_{i=1}^D K_i \mid (+ t_i)
 \] \]
 and then eliminate quantifier as and then eliminate quantifier as
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 $\exists res, i. \neg true$\\ $\exists res, i. \neg true$\\
 $false$ $false$
 +
  
  
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 Avoid transforming to conjunctions of literals: work directly on negation-normal form. Avoid transforming to conjunctions of literals: work directly on negation-normal form.
 +  * the technique is similar to what we described for conjunctive normal form
  
 This is the Cooper'​s algorithm This is the Cooper'​s algorithm