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sav08:idea_of_quantifier-free_combination [2009/05/13 10:37]
vkuncak
sav08:idea_of_quantifier-free_combination [2015/04/21 17:30]
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-====== Idea of Quantifier-Free Combination ====== 
- 
-We know of several classes of formulas that we can decide: 
-  * ground formulas interpreted over arbitrary functions and relations (also called uninterpreted function symbols) - congruence closure 
-    * $f(f(f(f(a)))) \neq a \land f(f(a))=a$ 
-  * term algebras (interpreted over Herbrand model) - unification 
-    * $cons(a,​b)=cons(c,​d) \land a \neq c$ 
-  * real linear arithmetic - linear programming such as Simplex 
-    * $x < y \land y < x + 1$ 
-  * integer linear arithmetic - integer linear programming (branch and bound, branch and cut), reduction to SAT 
-    * $x < y \land y < x + 1$ 
- 
-We wish to reason about quantifier-free formulas that contain all these different symbols in the same formula. 
- 
-The idea is to separate a quantifier-free formula into constraints that talk only about individual theories, and solve each constraint separately. 
- 
-We are checking satisfiability. $F$ is satisfiable iff each disjunct in its disjunctive normal form is satisfiable.  ​ 
-\[ 
-    F \ \ \leftrightarrow \ \ \bigvee_{i=1}^n C_i 
-\] 
-We therefore consider conjunctions of literals $C_i$. 
- 
-Consider a conjunction of literals $C$.  If we can group literals into blocks ​ 
-\[  
-    C \leftrightarrow C_1 \land \ldots \land C_n 
-\] 
-If one of the $C_i$ is unsatisfiable,​ then $C$ is unsatisfiable. 
- 
-The idea is to separate conjuncts into those specific to individual theories, and then solve each $C_i$ using a specialized decision procedure $P_i$ 
- 
-An important question is **completeness**:​ if each $C_i$ is satisfiable,​ is $C_1 \land \ldots \land C_n$ satisfiable? ​ We will show that, under certain conditions, this holds.