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sav08:herbrand_universe_for_equality [2008/04/02 20:36]
vkuncak
sav08:herbrand_universe_for_equality [2008/04/02 20:45]
vkuncak
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 ===== Constructing Model for Formulas with Equality ===== ===== Constructing Model for Formulas with Equality =====
  
-Let $S$ be a set of formulas in first-order logic with equality and $S'$ result of replacing '​='​ with '​eq'​ in $S$.  Suppose that $S \cup AxEq$ is satisfiable. ​ Let $(GT,I_H)$ be Herbrand model for $S \cup AxEq$. ​ We construct a new model using //​quotient//​ construction,​ described as follows. ​+Let $S$ be a set of formulas in first-order logic with equality and $S'$ result of replacing '​='​ with '​eq'​ in $S$.  Suppose that $S \cup AxEq$ is satisfiable. ​ Let $(GT,I_H)$ be Herbrand model for $S \cup AxEq$. ​ We construct a new model using //​quotient//​ construction,​ described as follows ​(recall notation in [[First-Order Logic Semantics]]).
  
 For each element $t \in GT$, define For each element $t \in GT$, define
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 \] \]
  
-Consequently+In particularwhen $R$ is $eq$ we have 
-\[ + 
-    I_Q(eq) = \{ ([t_1],​[t_2]) \mid (t_1,t_2) \in I_H(eq) \} = \{ (a,a) \mid a \in [GT] \} +$I_Q(eq) = $ ++| $\{ ([t_1],​[t_2]) \mid (t_1,t_2) \in I_H(eq) \} = \{ (a,a) \mid a \in [GT] \}$ 
-\]+
 that is, the interpretation of eq in $([GT],​I_Q)$ is equality. that is, the interpretation of eq in $([GT],​I_Q)$ is equality.
 +++