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sav08:herbrand_s_expansion_theorem [2008/03/24 11:38]
vkuncak
sav08:herbrand_s_expansion_theorem [2009/05/26 10:26]
vkuncak
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 **Example** **Example**
 +Let's consider the expanded formula $F=P(f(a)) \wedge R(a, f(a))$, then $p(F)=p_1 \wedge p_4$ 
  
-Define propositional model $I_P : V \to \{{\it true},{\it false\}\}$ by +Define propositional model $I_P : V \to \{\it true},{\it false\}$ by 
 \[ \[
     I_P(p(C_G)) = e_F(C_G)(I)     I_P(p(C_G)) = e_F(C_G)(I)
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   * set $propExpand(S)$ has a propositional model   * set $propExpand(S)$ has a propositional model
   * set $S$ has a model with domain $GT$   * set $S$ has a model with domain $GT$
 +
 +**Example:​** Take the first three clauses our example (from [[Normal Forms for First-Order Logic]]):
 +  * $R(x,g(x))$
 +  * $\neg R(x,y) \lor R(x,​f(y,​z)))$
 +  * $P(x) \lor P(f(x,a))$
 +Taking as domain $D$ the set of natural numbers, the structure $(D,​\alpha)$ is a model of the conjunction of these three clauses, where $\alpha$ is given by:
 +  * $\alpha(a) = 1$
 +  * $\alpha(c) = 2$
 +  * $\alpha(g)(x) = (x + 1)$
 +  * $\alpha(f)(y,​z) = y+z$
 +  * $\alpha(R) = \{(x,y).\ x < y\}$
 +  * $\alpha(P) = \{x.\ x \mbox{ is even} \}$
 +This model induces an Herbrand model $(GT,​\alpha_H)$,​ in which $\alpha_H(P)$ is a set of ground terms and $\alpha_H(R)$ is a relation on ground terms, $\alpha_H(R) \subseteq GT^2$. ​
 +
 +To determine, for example, whether $(f(a,​a),​g(g(a))) \in \alpha_H(R)$ we check the truth value of the formula
 +\[
 +   ​R(f(a,​a),​g(c)))
 +\]
 +in the original interpretation $(D,​\alpha)$. In this case, the formula reduces to $1+1 < 2+1$ and is true in the interpretation. Therefore, we define $\alpha_H(R)$ to contain the pair of ground terms $(f(a,​a),​g(c)))$.